(2x^-3y^2)^-4/(2x^2y)^-3

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Solution for (2x^-3y^2)^-4/(2x^2y)^-3 equation: 


D( x )

2*x^-3*y^2 = 0

x = 0

(2*x^2*y)^-3 = 0

2*x^2*y = 0

2*x^-3*y^2 = 0

2*x^-3*y^2 = 0

2*x^-3*y^2 = 0 // : 2*y^2

x^-3 = 0

x należy do O

x = 0

x = 0

(2*x^2*y)^-3 = 0

(2*x^2*y)^-3 = 0

1/8*x^-6*y^-3 = 0 // : 1/8*y^-3

x^-6 = 0

x należy do O

2*x^2*y = 0

2*x^2*y = 0

2*x^2*y = 0 // : 2*y

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

((2*x^-3*y^2)^-4)/((2*x^2*y)^-3) = 0

1/2*x^18*y^-5 = 0 // : 1/2*y^-5

x^18 = 0

x = 0

x in { 0} 

x belongs to the empty set

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